(
[ 1 0 1 1] [ 1 0 0 2]
[ 1 1 0 5] [ 0 1 0 3]
[ 1 0 2 0] [ 0 0 1 -1]
[ 1 -1 0 -1], [ 0 0 0 0]
)
Math 303: Section 25
\[ \def\R{{\mathbb R}} \def\P{{\mathbb P}} \def\B{{\mathcal B}} \def\C{{\mathcal C}} \def\b{{\mathbf{b}}} \def\x{{\mathbf{x}}} \def\y{{\mathbf{y}}} \def\u{{\mathbf{u}}} \def\v{{\mathbf{v}}} \def\w{{\mathbf{w}}} \def\z{{\mathbf{z}}} \def\M{{\mathcal{M}}} \DeclareMathOperator{\null}{Nul} \DeclareMathOperator{\span}{Span} \DeclareMathOperator{\dim}{dim} \newcommand{\set}[1]{\left\{ {#1} \right\}} \newcommand{\setof}[2]{{\left\{#1\,\colon\,#2\right\}}} \]
Takeaway: Bases give coordinate systems!
Definition 1 Let \(\B = \set{\v_1, \v_2, \ldots, \v_n}\) be a basis for a vector space \(V\). For any vector \(\x\) in \(V\), the **coordinate vector of \(\x\) with respect to \(\B\) is the vector
\[ [\x]_{\B} = \left[\begin{matrix} x_1 \\ x_2 \\ \vdots \\ x_n \end{matrix}\right], \]
where
\[ \x = x_1 \v_1 + x_2 \v_2 + \cdots + x_n \v_n. \]
The scalars \(x_1, x_2, \ldots, x_n\) are the coordinates of the vector \(\x\) with respect to the basis.
Let \(\mathcal{S} = \set{1,t}\) and \(\B = \set{3+2t, 1-t}\). Assume that \(\mathcal{S}\) and \(\B\) are bases for \(\P_1\). Find \([3+7t]_{\mathcal{S}}\) and \([3+7t]_{\B}\).
Definition 2 Let \(V\) be an \(n\)-dimensional vector space with basis \(\B\). The coordinate transformation \(T\) from \(V\) to \(\R^n\) with respect to the basis \(\B\) is the mapping defined by
\[ T(\x) = [\x]_{\B} \]
for any vector \(\x\) in \(V\).
Let \(a(t) = 8 + 2t\) and \(b(t) = -5 + t\) in \(\P_1\). Suppose we know that \(\C = \set{1+t, 2-t}\) is a basis of \(\P_1\). Let \(T(\x) = [\x]_{\C}\) for \(\x\) in \(\P_1\).
Theorem 1 If a vector space \(V\) has a basis \(\B\) of \(n\) vectors, then the coordinate mapping \(T : V\to \R^n\) defined by \(T(\x) = [\x]_{\B}\) satisfies
Let \(V\) be a vector space with an ordered basis \(\B = \set{\v_1, \v_2, \ldots, \v_n}\). Then \(T\) maps \(V\) into \(\R^n\). Let’s show that \(T\) maps \(V\) onto \(\R^n\).
Let \(\mathbf{b} = [b_1 \ b_2 \ \cdots \ b_n]^{\textsf{T}}\) be a vector in \(\R^n\). Must there be a vector \(\v\) in \(V\) so that \(T(\v) = \mathbf{b}\)? If so, find such a vector. If not, explain why not.
Theorem 2 If a vector space \(V\) has a basis \(\B\) of \(n\) vectors, then the coordinate mapping \(T : V\to \R^n\) defined by \(T(\x) = [\x]_{\B}\) is both one-to-one and onto.
Let \(V = \P_3\) and let \(\B = \set{1, t, t^2, t^3}\). Let \(S = \set{1+t+t^2+t^3, t - t^3, 1+ 2t^2, 1+ 5t - t^3}\).
sage
(
[ 1 0 1 1] [ 1 0 0 2]
[ 1 1 0 5] [ 0 1 0 3]
[ 1 0 2 0] [ 0 0 1 -1]
[ 1 -1 0 -1], [ 0 0 0 0]
)